please empty your brain below
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Comments not answering the current question will be shifted here: comments (32)
diamond geezer | Homepage | 03.01.19 - 8:00 a.m. | #
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a) 99 years ago.
Regards
zin92 | 03.01.19 - 8:13 a.m. | #
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b) 1920
Cheers
Steve | 03.01.19 - 8:58 a.m. | #
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c) 9 years
mcf | 03.01.19 - 9:03 a.m. | #
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D) 2028
Tom | 03.01.19 - 9:21 a.m. | #
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e) 9.
zin92 | 03.01.19 - 10:17 a.m. | #
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f) 10
mcf | 03.01.19 - 10:27 a.m. | #
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g) 22nd century.
zin92 | 03.01.19 - 10:32 a.m. | #
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h) 13th century
Rob Miller | Homepage | 03.01.19 - 10:36 a.m. | #
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i) Between the years 2910 and 3009
Rob Miller | Homepage | 03.01.19 - 10:40 a.m. | #
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j) Between the years 3900 and 4008
mcf | 03.01.19 - 10:54 a.m. | #
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k) 40th century
Rob Miller | Homepage | 03.01.19 - 11:37 a.m. | #
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l) 63 times
Rob Miller | Homepage | 03.01.19 - 11:41 a.m. | #
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Hurrah!
Now open for more general comments...
diamond geezer | Homepage | 03.01.19 - 11:47 a.m. | #
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m) The year must be a multiple of three.
JubileeLine | 03.01.19 - 12:18 p.m. | #
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A very enjoyable puzzle that distracted me handily from my first morning back at work!
Here's an ugly Ruby script that calculates and outputs all of the answers: https://gist.github.com/robmiller/b416df...
Rob Miller | Homepage | 03.01.19 - 12:53 p.m. | #
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Well done Rob. I questioned the answer to k until I checked that centuries run from nn01 to nn00. So the last year of the century is the only year which shares the digits with the century eg 2000 is in the 20th Century
I was thinking whether I could work it out using SQL commands but early January malaise got the better of me
Scientist | 03.01.19 - 1:41 p.m. | #
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m) The year must be 3 more than a multiple of 9 (related to all multiples of 9 having digits that add up to a multiple of 9).
The list of years is infinite, as even a huge number with hundreds of digits could have lots of zeroes with the other digits still only adding up to 12; in particular, 10 times any valid number will also be valid.
Rich G | Homepage | 03.01.19 - 11:11 p.m. | #
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